What are the zeros of the quadratic function f(x) = 6×2 + 12x – 7? Question What are the zeros of the quadratic function f(x) = 6×2 + 12x – 7? in progress 0 Math Kennedy 2 days 2021-10-11T00:21:11+00:00 2021-10-11T00:21:11+00:00 2 Answers 0

## Answers ( )

Answer:-6 ± √78\6 [0.47196014…, -2.47196014… = x]

Step-by-step explanation:The roots [zeros] are the x-values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

Answer:x = 1 + √74/6orx = 1 – √74/6Step-by-step explanation:Points to remember

Zeros of a quadratic equation ax² + bx + c = 0

x = [-b ± √(b² – 4ac)]/2a

To find the zeros of given quadratic equationIt is given that,

6x² +12x – 7 = 0

Here a = 6, b = -12 and c = -7

x = [-b ± √(b² – 4ac)]/2a

= [-12 ± √(12² – 4*6*(-7))]/2*6

= [12 ± √(144 +168 )]/12

= [12 ± √312]/12

= [12 ± 2√74]/12

= 1 ± √74/6

x = 1 + √74/6andx = 1 – √74/6